The **coefficient** of** friction **between the boy's shoes and the ice is **0.65**.

The coefficient of **static friction** for ice is 0.65, so this means that 65% of the **force** needed to move an object from one place to another must be applied in order to get it moving across the ice at all—once it starts moving, however, there will be a lot less **work** required because we have already accounted for the initial force required to start moving it.

This means that if we want our boy running north at** 5 meters **per second across this large, flat lake with no wind or waves or anything else going on that might cause him trouble (or even help him), he'll need 10 meters per second or more just to get started.

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Jupiter has a gravitational field of 23.6 N/kg. Would you weigh more or less on Jupiter than you do on Earth?

Earth's **gravitational field** = 10N/kg

Jupiter's gravitational field = 23.6 N/kg

Jupiter's gravitational field > Earth's gravitational field

Therefore, we will **weigh more **on Jupiter.

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Number the steps for balancing equations:

Use coefficients to increase the atoms on each side.

Check to make sure you have the same number of each type of atom on each side.

Count the atoms on each side.

Identify the atoms on each side

The steps for **balancing **the equation is 3, 4, 2 and than 1. The **balanced equation **is very important for **chemical reaction**.

A **balanced chemical equation **is defined as a **formula **where **both **the reactants and the products have the **same **amount of atoms of each kind.

It can also be defined as an **equation **for a **chemical reaction **that accounts for the overall charge and the number of atoms for each reacting element.

**Steps **for balancing the chemical equation

Thus, the steps for **balancing **the equation is 3, 4, 2 and than 1. The **balanced equation **is very important for **chemical reaction**.

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BRAINLIEST + THANKS GIVEN

What happens to the brightness of lightbulbs if you add them to each circuit?

Adding bulbs to a series will make them dimmer because current is reduced, adding bulbs to a parallel will make them brighter because the current through each individual bulb goes up.

Adding bulbs to a series will make them brighter because each bulb will take more current, adding bulbs to a parallel will not affect the brightness because the current through each individual bulb remains the same.

Adding bulbs to a series will make them dimmer because current is reduced, adding bulbs to a parallel will not affect the brightness because the current through each individual bulb remains the same.

Adding bulbs to a series will make them brighter because current is increased, adding bulbs to a parallel will make them dimmer because the current has to be split up between them.

Adding bulbs into a **series** will make them **dimmer** because the current is decreased, adding bulbs to a **parallel** will not affect the **brightness** because the current through each individual bulb remains the same.

Therefore, Option (C) is correct.

What are series circuits and parallel circuits?A **series circuit **is one where the same current flows through all the components in the circuit. The current has only **one path **in series circuits. A **parallel circuit** is one where the electric current has** multiple paths **to flow through. The components of the parallel circuits will have the same voltage across all ends.

When we connect bulbs in the circuit where all are connected in **series** then the net **resistance** of the circuit will increase and the **voltage** across each bulb will decrease.

Since **voltage** decreases across each bulb then the current across each bulb will decrease and the bulb gets dimmer because the **current** is reduced.

When we connect bulbs in **parallel** the **voltage **and** current** across each bulb will remain the same and then adding bulbs to a parallel will not affect the brightness.

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If two balls the same size and different masses go down a ramp, which ball would have more speed? (The greater mass or the less mass?)

If two balls the same size and different masses go down a ramp, they will move at the **same **speed.

The phrase "rolling down a frictionless slope" is illogical. The **translational **and **rotational **motions of the balls are completely uncoupled if the slope has no friction, and the balls just slide down the slope.

I believe the situation when there is **static **friction, allowing the balls to roll without slipping, is what you are most interested in.

In either case, the velocity as a function of distance along the ramp** (v(s))** for uniform spheres ends up being **independent **of both the mass and the radius. Additionally, the duration of the descent is simply the integral of **ds/v(s)**, which is also independent of the mass and radius.

As a result, they move at the **same **speed **regardless **of **position **and arrive at the bottom at the same moment.

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Help!!

Batman is chasing the joker. If, while gliding down towards him at 75 m/s, it takes him 30 seconds to catch him, how far away was the joker? And how many kilometers is that?

If it takes 30 seconds for the **Batman** to catch the** joker** while gliding towards him at 75 m/s, batman is **2,250 meters** away from the joker. In kilometers, the distance is **2.25 kilometers. **

**Distance** is calculated by the product of the speed and time.

The speed of the batman is 75 m/s and the time taken by the batman to catch the joker is 30 seconds.

Hence the distance between joker and batman is calculated as:

Distance = 75 m/s × 30 s = 2250 meters

According to unit conversion from meters to **kilometers**, 1 kilometers has 1000 meters. Hence the distance in kilometers is, 2.25 kilometers.

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a rowboat is being pulled by two ropes tied to the front of the boat. one rope is along the x-axis direction and exerts a force of 50 n. the other is along the y-axis direction and exerts a force of 100 n. what is the magnitude of the net force that the ropes exert on the boat?

If the two known sides of the **force **triangle are drawn to scale, we can determine the magnitude of the resultant vector by measuring the length of the vector and by the scale factor used for the other two sides.

The size of the **force **triangle can be determined by measuring the length of the resultant vector and multiplying it by the **scale **factor used for the other two sides if the two known sides of the force triangle are drawn to **scale**. We can measure its angle using a compass from the same reference line to determine its direction.

The force triangle must be drawn accurately, and the length and angle of the resulting triangle must be measured precisely for the graphical approach to be accurate. Consequently, a significant mistake could be introduced.

Using the laws of sines and cosines to solve for the resultant is an alternate method. To do this, we must first identify the **scale **force triangle's angle b. Since the opposite corners of a parallelogram have identical angles, we may calculate the value of b using the **force **parallelogram given below.

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A car travels at 15 m/s for 10,0s. It speeds

up with an acceleration of 0.2 M/S² for 15.0 s. At the

end of this time What is its velocity?

If **acceleration**, acceleration would be too fast in square metres. Therefore, this information equals the final minus **initial** divided by a, which is **15 m/s minus **5 m/s divided by 2 m/s squared. Five seconds are involved.

The three different forms of** projectile motion **are as follows: motion of a horizontal projectile. **projectile motion **that is **oblique**. **Motion **of a **projectile** on an incline

An item or particle that is thrown toward the surface of the Earth and moves along a** curved route **only under the** influence of gravity** is said to be experiencing projectile motion.

The **movement** of a falling item (projectile) after being assigned a forward beginning velocity The only forces affecting a **projectile** are **gravity** and **air resistance.** The ball travels along a curved route as a result of its initial forward velocity and the **downward** vertical **pull of gravity.**

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A cat lies on the floor. Which of the following statements are correct?

a,Cannot be known

b,Support Force < Weight

c,Support Force > Weight

d,Support Force = Weight

help pls asab

**Answer:**

Choice d: support force (normal force) on the cat and the weight of the cat are equal in magnitude.

**Explanation:**

The cat in this question is stationary. As a result, the acceleration of this cat will be zero. By Newton's Second Law of Motion, the net force on this cat will also be zero.

If the floor is level, there will be two forces acting on this cat:

The weight of the cat, which points downwards.The support force (normal force) of the floor on the cat, which points upwards.For the net force to be zero, these two forces need to balance each other. For that, they need to have the same magnitude and point in opposite directions. Therefore, the magnitude of the support force (normal force) will be equal to the magnitude of the weight of this cat.

9. NL5Q9

A rightward force of 14.0-N is exerted on a block to accelerate it across a friction-free surface. It accelerates at 3.45

m/s/s. If a second block of identical mass is dropped onto the first block, then what is the acceleration when the same

14.0-N force is applied to it. (Assume that there is no sliding between the first and second block.)

A **force **is a power that can exchange the movement of an object. A pressure can reason an object with mass to exchange its pace, i.e., to boost up. force can also be described intuitively as a push or a pull. A force has both value and path, making it a **vector amount**.

**Acceleration **is the price of change of the rate of an item with admire to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the internet **pressure **acting on that item

**Force = mass × acceleration**

since friction is zero

mass = Force / acceleration

= 14 / 3.45

= 4.0579 kg

On adding a second block of the same **mass **

total mass = 4.0579 + 4.0579 kg

= 8.2 kg

new,

acceleration = force/ mass

= 14/8.2

= 1.7073 m/s²

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The acceleration of a moving object is given by the function a=8t+4. the object is initially 2m from the origin and moving to the right with a speed of 4 m/s. find the velocity at t=3s

The particle's speed at t=1 is 4 + 2 = 6 m/s. The particle moves at a speed of 4+22=8 m/s when t=2. The particle's **velocity **is 4+2t m/s after t seconds.

We presented the kinematic functions of velocity and acceleration using the derivative in Instantaneous Velocity and Speed and Average and Instantaneous **Acceleration**.

The **velocity **function was discovered by taking the derivative of the position function, and the acceleration function was discovered by taking the derivative of the velocity function.

We can calculate the velocity function from the **acceleration **function and the position function from the velocity function using integral calculus.

A particle travelling in a straight line whose **velocity **drops from 5 m/s to 2 m/s uniformly over the course of one second experiences a constant acceleration of 3 m/s2.

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Please Help Me!!

Imagine your friend was absent from class today. In your own words, explain how you can use water to measure the volume of an object.

You can take a box like the same size and you can take annother but as a box and pour water into it and you can see how much water is in that level.

a slender uniform rod 100.00 cm long is used as a meter stick. two parallel axes that are perpendicular to the rod are considered. the first axis passes through the 50-cm mark and the second axis passes through the 20-cm mark. what is the ratio of the moment of inertia through the second axis to the moment of inertia through the first axis?

the **ratio **of the moment of inertia through the second axis to the moment of inertia through the first axis is** 0.676**

The second **axis** is at the centroid of the rod.

The length of the rod is L = 100 cm = 1 m

The first** axis** is located at 20 cm =** **0.2 m from the centroid.

Let m = the mass of the rod.

The moment of inertia about the centroid (the 2nd axis) is

Ig = ml^3/12 = (m kg) (1 m)^2/12 = m/12 kg - m^2

The parallel axis theorem states that

I1 = m/12+0.04 **m** = 0.1233 m kg - m2 is the **moment of inertia** about the first axis.

The ratio of the **moment of inertia **through the centroid of the second axis to the first axis is

Ig/I1= 0.0833 m / 0.1233 m = **0.676**

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Two cars, each having a mass of 1,000 kg are being tested at the Department of Highway Safety facility. Car A is moving at 30 m/s to the north. Car B is moving at 15 m/s to the south. When they collide, which of the following is true?

a- Car A applies a greater force on car B than car B applies on car A.

b- Car A applies a force on car B equal to the force car B applies on car A.

c- Car B applies a greater force on car A than car A applies on car B.

d-Car A and car B do not have the same velocity; you cannot compare the forces.

Two cars, each having a mass of 1,000 kg are being tested at the Department of Highway Safety facility. Car A is moving at 30 m/s to the north. Car B is moving at 15 m/s to the south. When they collide a- Car A applies a greater **force **on car B than car B applies on car A.

Momentum, product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction. Isaac Newton's second law of motion states that the time rate of change of momentum is equal to the force acting on the particle.

When both the cars will collide , one with greater momentum will applies greater force .

As **momentum **is calculated as mass multiplied by velocity , since both the car have same mass then the car with a greater velocity will exert more force on the other car .

since , car A has a velocity of 30 m/s and car B is moving with a velocity of 15 m/s , then car A will have greater momentum and will exert a greater force on car B.

correct option will be

a- Car A applies a greater force on car B than car B applies on car A.

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Why is it necessary to collimate the light source before using the prism to disperse the light?.

It necessary to **collimate** the light source before using the prism to disperse the light in order for the light rays entering the prism to be **parallel.**

**Collimator **is a tool for converting a point source's divergent radiation into a **parallel beam**. To perform specific measurements in **spectroscopy, geometrical optics, **and** physical optics**, the light must be collimated.

An optical collimator is made up of a tube with a **convex lens** at one end and a **variable aperture** at the other end that is located in the lens' focal plane. To examine the image without parallax, **radiation** entering the aperture exits the collimator as a parallel beam.

Hence, collimation is needed for the light rays entering the prism to be **parallel.**

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3. A penguin waddles 8 m uphill before sliding back down to its friends in 2 seconds. If the penguin ends where it started, what is its velocity?

The **velocity **of penguin as he ends where he started was **0 m/s.**

What is displacement?

Displacement is the **length **of straight line** **joining the **initial** and **final **position of the body.

Given is a penguin who waddled **8 m** uphill before sliding back down to its friends in** 2 seconds. **

We know that the velocity is the **rate of change** of **displacement **with respect to **time**. Mathematically -

**v = dx/dt**

dx = v dt

∫dx = ∫v dt

Δx = vΔt

**v = Δx/Δt**

Now, the **displacement** of the penguin will be = **Δx** = 8 - 8 =** 0**

Then, its **velocity **will be -

v = 0/Δt = 0

Therefore, the **velocity **of penguin as he ends where he started was **0 m/s.**

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to sharpen a knife, you push with a force of 5n so that the edge of the knife is against a stone. the stone will sharpen the knife if it is spinning. the 30cm diameter stone is spinning at 200rpm and has a mass of 30kg. the coefficient of kinetic friction between the knife and the stone is 0.30. after 10 seconds of grinding what is the angular speed of the stone?

The final **angular** **speed** will be 194 rpm.

From the statement:

force = 5 N

**mass **of the stone = 30 kg

**diameter **of the stone = 30 cm = 0.30 m

the radius of the stone will be = 0.15 m

initial angular velocity = 200rpm

coefficient of kinetic friction = 0.3

time for which knife kept on stone = 10 s

moment of inertia (I) = 0.5mr² (considering the stone as a solid ring )

= 0.5 (30 × (0.15)²)

= 15 × 0.0225

= 0.3375 kgm²

Now ,we know that

**torque** = I α

Also torque = F x r (r = perpendicular distance )

here force will be μF = 0.3F

therefore ,

Iα = μF × r

0.5 (30 × (0.15)²) × α = 0.3 × 5 × 0.15

∴ α = 0.6

the value of **acceleration **will be negative as the wheel is slowing down

∴ α = - 0.6

Now , using the 1st equation of motion

ω' = ω +αt

ω' = 200 -0.6 (10)

ω' = 194 rpm.

Hence the **angular** **speed **of the stone will be 194 rpm.

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Tell us what you know about the nursing profession. How are you an underrepresented minority in nursing or an economically disadvantaged student?

The **nursing profession** offers specialized care from infancy to death. Social, **psychological**, and **economic** issues are some of the challenges faced by **minority nurses.**

It is the **nurse's responsibility** to maintain continuity of care and develop a close closeness with the **patient** in order to** foster trust **and foster a climate that is safe for recovery. Numerous **worldwide nursing** codes of practice presently **endorse patient **advocacy.

**Health promotion** is promoted by nurses, who also **teach patients** and the general public how to avoid **disease** and** damage**, care for patients and help with** treatment,** take part in **rehabilitation**, and offer support. No other **medical specialis**t has a job with such a wide-ranging and complex scope.

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A weight training ball is put on a ledge 3 m high. The potential energy of the ball on the

ledge is 200 J. What is the mass of the ball? Round your answer to the nearest tenth.

Rearrange the formula to solve for mass.

Use the formula to solve for the mass of the ball.

The **mass **of the ball is 6.8 kg.

A metric called **mass **is employed in physics to express inertia, a basic property of all **matter**. What it essentially is is the resistance of a mass of matter to changing its **direction **or **speed **in response to the application of a force.

Mass is not the same as weight in **physics**, despite the fact that weight is commonly determined using a **spring scale **rather than a balanced scale and directly compared with known masses. An object would weigh less on the Moon than it does on Earth despite maintaining the same mass because of the lower **gravity **there.

We know that the formula of **potential energy** is,

**P.E = mgh**

Where m is the** mass of the object **g is the acceleration due to **gravity **and h is the height.

Given :

PE = 200 J

g =9.8 m/s^2

**h = 3m **

Therefore according to the question,

3 x 9.8 x m = 200

=> m = 200 / 3 x 9.8

**=> m = 6.8 kg**

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\tusain bolt's record time for running the 100 meter dash is 9.58 seconds. if bolt had a mass of 94 kg at the time of his record-breaking run, what was his average momentum along the straight-line path?

his average **momentum** along the straight-line path id 981.21kgm/s

**What is momentum ?**

momentum is the result of a particle's **mass and velocity**. Being a vector quantity, **momentum** possesses both magnitude and direction. According to Isaac **Newton's **second equation of motion, the force applied on a particle is equal to the time rate of** change of momentum. **

According to **Newton's second law**, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum. On the other hand, a particle's** momentum **represents the length of time needed for a consistent force to bring it to rest.

Average velocity,

v = distance / time

= 100 m / 9.58 s

= 10.44 m/s

Now use:

momentum = m*v

= 94 Kg * 10.44 m/s

= 981.21 Kg m/s

Answer: 981.21 Kg m/s

his average** momentum **along the straight-line path id 981.21kgm/s

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A hollow metal sphere is charged to a potential of 40 V. The potential at its center is ________.Group of answer choices0 V80 VDepends on the radius of the sphere-49 V40 V-80 V

**40 V**

**Explanation**

Electric potential at any point inside a hollow metallic sphere is constant. Therefore, if potential at surface is 40 V, potential at centre will also be 40 V.

40V

also In a hollow sphere, with the charge on the surface of spheres, there is no charge enclosed within the sphere, since all the charges are in surface. Hence there is no electric field within the sphere.

I hope this helps you

a rugby player passes the ball 8.25 m across the field, where it is caught at the same height as it left his hand. at what angle was the ball thrown if its initial speed was 12.0 m/s, assuming that the smaller of the two possible angles was used?

Of the two possible** angles**, the smaller angle is θ = 17.075°.

The distance between a projectile's launch point and its point of impact with the ground, assuming it is fired from the ground, is referred to as the **range**.

R = [u²sin (2θ)]/g

Given values;

**Range** of pass; R = 8.25 m

Speed; u = 12 m/s

R = [u²sin (2θ)]/g

Thus;

8.25 = 12² × (sin(2θ))/9.8

(sin(2θ)) = ( 8.25 × 9.8)/12²

(sin(2θ)) = 0.5614

2θ = sin⁻¹(0.5614)

2θ = 34.15

θ =34.15/2

θ = 17.075°

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the student measured the volume of each fruit three times and then calculated a mean value the three measurements for a grape were 2.1cm3 2.1cm3 2.4cm3

The mean value of the **measurements **is 2.2 cm³.

The attributes of an object or an event are **measured **and **quantified **so that they can be compared to other things or events.

Therefore, **measurement **is the process of determining the size or smallness of a physical quantity in comparison to a primary reference quantity of a similar kind. The range and **applications **of **measurement **depend on the situation and industry.

**Measurements **do not apply to nominal attributes of things or occurrences in the natural sciences and **engineering**, as stated in the International Vocabulary of Metrology published by the International Bureau of Weights and Measures. **Measurement **is essential to trade, science, **technology**, and quantitative research in many fields.

Mean of the **measurements** = (2.1+2.1+2.4)/3 = 6.6/3 = 2.2 cm³.

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consider the sprint of a quarter horse that has a maximum speed of 24 m/s and a maximum acceleration of 5.7 m/s2 (example 3.17 in the textbook). model the horse's velocity and acceleration with exponential functions.

Distance horse run with maximum **acceleration **at t = 2.0 s is **s1=11.4 m** , t = 4.0 s is **s2=45.6 m** and t = 8.0s is **s3 = 141.54 m.**

An object that is speeding occasionally has a constant change in **velocity **over time. As was said in the previous sentence, the data table above depicts an object increasing its velocity by 10 m/s every second. Since there is a constant change in **velocity **every second, this is known as a constant acceleration. Contrary to popular belief, an object with constant acceleration is distinct from one with constant **velocity**. Refuse to be duped! Furthermore, a moving item at a constant speed is not accelerating. The following data tables show the motions of objects moving at a constant acceleration and at a variable **acceleration**. The three main categories of accelerated motions are uniform, non-uniform, and average acceleration. When an item moves in a straight path with an increase in speed occurring at regular intervals of time, this motion is referred to as having uniform acceleration.

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What is the wavelength in nanometers of light with a frequency of 2. 840 × 1014 hz?.

The wavelength is:** 671nm (red light).**

**Wavelength** relates to **frequency** as follows:

**λ=vf**

in which f is the frequency,

v is the speed of light, and

λ is the wavelength.

Filling this in for the example:

v=3⋅108ms f=4.47⋅1014

Hz=4.47⋅1014s−1λ

=3⋅108ms4.47⋅1014s−1

=6.71⋅10−7m

from m to nm is ⋅109

So the wavelength is: **671nm (red light).**

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the coefficient of kinetic friction between the ramp and the lower box is 0.441, and the coefficient of static friction between the two boxes is 0.834. what force t do you need to exert to accomplish this?

**Newton's second law** states that the product of the box's mass and acceleration determines the net force acting on the object. T, which equals **f= 23.52 N**, must be applied in order to move up the ramp.

The behaviour of objects for which all external **forces **are balanced is predicted by Newton's first law of motion. According to the first law, sometimes known as the law of inertia, an object's acceleration will be zero metres per second per second if the **forces **acting on it are evenly distributed. When everything is in balance, or equilibrium, objects cannot accelerate. According to Newton, an item will only accelerate if another force is operating on it that is net or imbalanced. If an imbalanced force is present, the object will accelerate and change its direction and speed, or both. The behaviour of objects for whom all external **forces **are not balanced is covered by** Newton's second law** of motion.

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Calculate the kinetic energy of a 1000 kg car moving at 4 meters per second

**Kinetic Energy** = 1/2 * m *(v*v)

M= 1000

V=3 m/s

KE=1/2 * 1000 * (4*4)

KE= 500*16= **8000 J**.

To calculate** kinetic energy** Find the square of the object's** velocity.** Multiply this square by the mass of the object. The product is the kinetic energy of the object. The kinetic energy of a moving car is KE=1/2mv^2. Create and test a function called KE to find the kinetic energy of a moving car given a vehicle mass m and velocity v.

As every engineer knows calculating** energy** is easy. The **unit **of electrical energy is the kilowatt hour. It is determined by multiplying the amount of electricity consumed by the number of hours the electricity was consumed. Multiply this by the cost per kWh to get the total energy cost. There are five main types of kinetic energy radiant thermal, sound electrical, and mechanical energy. Radiant energy is related to ultraviolet and gamma rays that are constantly moving through space. Acoustic energy is kinetic energy in the form of vibration or noise.

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**Answer:**

Kinetic energy = 8 KJ

**Explanation:**

Given information,

→ Mass of car = 1000 kg

→ Velocity = 4 m/s

Now we have to,

→ Find the required Kinetic energy.

Let us **assume** that,

→ Kinetic energy = x

The **formula** we use,

→ KE = (1/2)mv²

Then the **value of x** will be,

→ x = (1/2)mv²

→ x = (1/2) × 1000 × (4)²

→ x = (1000/2) × 16

→ x = 500 × 16

→ x = 8000 J

→ [ **x = 8 KJ** ]

Hence, the answer is 8 KJ.

A wave crest passes a particular point every [tex]\frac{1}{10}[/tex] th of a second. Calculate the frequency of the wave.

**Answer:**

**Explanation:**

Given:

T = 1/10 s -** Wave oscillation period**

_____________________________

f - ?

**The frequency of the wave:**

f = 1 / T = 1 / (1/10) = 10 Hz

a 5.0 g coin is placed 15 cm from the center of a turntable. the coin has static and kinetic coefficients of friction with the turntable surface of and the turntable very slowly speeds up to 60 rpm. does the coin slide off

The turntable rotates very slowly at 60 rpm, hence the coin does not **slide off** as the **static friction force** is greater than the** **centripetal force.

Missing data from the question:

Static **coefficients of friction** (μs) = 0.8

Kinetic coefficients of friction (μk) = 0.5

There are two forces works on the coin, the** friction force** and the **centripetal force**. The coin will start to slide off if the centripetal force is equal to the maximum static friction force.

Let:

Fs = static friction force

Fc = centripetal force

Fs = μs . mg

Fc = m . v²/R = m . ω²R

Where:

m = coin's mass

g = gravitational acceleration = 10 m/s²

ω = **angular velocity**

Parameters given:

R = 15 cm = 15 . 10⁻² m

m = 5 gram = 5 . 10⁻³ kg

ω = 60 rpm = 60 . 2π/60 = 2π rad/s

Hence,

Fs = μs . mg = 0.8 . 5 . 10⁻³ . 10 = 4 . 10⁻² N

Fc = m . ω²R = 5 . 10⁻³ . (2π)² . 15. 10⁻² = 2.96 .10⁻² N

Since Fs > Fc, hence the coin does not slide off.

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What happens to the mechanical energy of the apple as it falls from the tree?

Answer:

When an apple falls from a tree tothe ground, the potential energy ofthe fall is converted into kineticenergy,which is kinetic energy. Whenan apple hits the ground, it convertskinetic energy into heat energy

Explanation:

**Question: **

What happens to the mechanical energy of the apple as it falls from the tree?

**Answer:**

When the apple falls from the tree, it has some gravitational potential energy due to its height. When it fails, the Gravitation Potential energy will begin converting into Kinetic Energy.

A 5 kg block is pulled with 3.5 N of force to the right. The block experiences 0.5 N of friction. What is the acceleration of the block?

A 5 kg block is pulled with 3.5 N of **force** to the right. The block experiences 0.5 N of **friction**. The **acceleration** of the block will be 0.6 m/s^2.

According to **Newton's second law of motion**, force is calculated as mass times acceleration. **Acceleration** is the rate of change of velocity.

Here, the block is moved to right side by applying 3.5 N force. The block experienced a **frictional force** of 0.5 N. Then the **total force** is,

F_(net) = 3.5 N - 0.5 N = 3 N

The **mass** (m) of the block is 5 kg. The acceleration of the block will be

Acceleration (a) = Force/Mass

a = F_(net)/m

a = 3/5 = 0.6 m/s^2

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