To find the midpoint of the given line segment, we need to find the mean of the x coordinates and the y coordinates of the given points:

[tex]\begin{gathered} x=\frac{4+(-6)}{2}=-\frac{2}{2}=-1 \\ y=\frac{-2+2}{2}=0 \end{gathered}[/tex]It means that the midpoint is M = (-1,0).

give me a multi step equation with an answer of -8

A **multi step equation** with an answer of -8 can be expressed as: 2x + 20 = 4.

x = -8 when solved.

What is a Multi Step Equation?A **multi step equation** can be an **equation** that has variables or/and terms on both sides, of which we can solve for the variable in the equation by isolating the variable to one side of the **equation** using inverse operations.

For example, a **multi step equation** can be expressed as 2x + 20 = 4.

Solve for x in the **equation**:

2x + 20 - 20 = 4 - 20 [subtraction property of equality]

2x = -16

2x/2 = -16/2 [division property of equality]

x = -8

Thus, 2x + 20 = 4 is a **multi step equation** that has a solution of -8.

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9s-5t=-4u solve for s

**Answer: s= -4u/9 + 5t/9**

**Step-by-step explanation: Hope it helps**

**Step-by-step explanation:**

First of all, we have to take -5t to the other side and after taking it to the other side it will be +5t, then we have to take (only) 9 to the other as it is 9s (multiplication) it will be division if u take it to the other side.

Done

Swimming pool on a certain hot summer day, 606 people used the public swimming pool the daily prices are $1.75 for children and $2.50 for adults the receipts for admission totaled $1357.50. How many children and how many adults swam at the public pool that day

On a hot summer day, 606 people used the **public swimming pool**; daily admission prices are $1.75 for children and $2.50 for adults; admission receipts totaled $1357.50; **396 adults** and **210 children** swam at the **public pool** that day.

Therefore,

1.75C + 2.50A = 1357.50

**C + A = 606**

C = 606-A

1.75(606 - A) + 2.50A = 1357.5

1060.5 - 1.75A + 2.50A = 1357.5

1060.5 + 0.75 A = 1357.5

0.75 A = 297

A = 297/0.75

A = 396

No of **adults** =** 396**

Therefore children = 606-396

No of **children** =** 210**

**396** adults and **210 **children swam at the** public pool** that day

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Please help

:(

It’s due

**Answer: 28**

**Step-by-step explanation: 28**

How can I do point-slope form?through (-5, 3), slope= -8/5

**ANSWER**

y - 3 = -8/5 (x + 5)

**EXPLANATION**

The point-slope form of the equation of a line, that has a slope m and passes through point (x1, y1) is:

[tex]y-y_1=m(x-x_1)[/tex]In this problem m = -8/5 and the given point is (-5, 3). The equation is:

[tex]y-3=-\frac{8}{5}(x+5)[/tex]write an equation for the line parallel to y 3x - 8 through the point (-2,-7)

**Answer:**

y = 3x - 1

**Step-by-step explanation:**

In order for lines to be parallel, they must have the same slope.

The slope of y = 3x - 8 is 3.

Now, we can solve it using point-slope form. Remember that m = 3, x₁ = -2 and y₁ = -7:

y − y₁ = m(x − x₁)

y - (-7) = 3(x - (-2))

y + 7 = 3(x + 2)

Distribute 3 and isolate y:

y + 7 = 3x + 6

y = 3x - 1

A bag contains 8 red marbles, 3 blue marbles, and 1 green marble. Find P(not blue).

a. 9

C.

1

4

b.

413

d.

314

**Answer:**

3/4

**Step-by-step explanation:**

**Probability**

8 red marbles, 3 blue marbles, and 1 green marble = 12 total marbles

8 red marbles+ 1 green marble = 9 not blue marbles

P ( not blue ) = not blue marbles / total marbles

= 9/12 = 3/4

**Answer:**

9

**Step-by-step explanation:**

8+3+1=12

12-3=9

umm ok i think i got it wrong or overcomplicated it lol

hope this helped

A material’s density is a measure of its mass per unit volume. In other words, D = M

V

. Use

this relationship to calculate the density of a shiny metal object whose mass was 200 g,

and whose volume was measured to equal 10.4 mL. Round answer to 1 d.p.

The **density** of the material of mass 200 g and volume 10.4 ml is 19.2 g/ml.

According to the question,

We have the following information:

Density is defined as the **mass **per unit volume.

So, we have the formula of density:

Density = Mass/volume

Mass of the metal object = 200 g

Volume of the metal object = 10.4 ml

Density = 200/10.4 g/ml

Density = 19.231 g/ml

Now, we will **round** it off to nearest 1 decimal point.

We know that when the digit is greater than 5 then the number is increased by 1 and when the digit is less than 5 then the number remains same.

So, we have:

Density = 19.2 g/ml

Hence, the density of the metal object is 19.2 g/ml.

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[02.06]

Solve and graph the absolute value inequality: 12x + 4 > 8. (1 point)

-9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9

-9-8-7 -6 -5 -4 -3 -2 -1 0 1 2 3 4

5 6 7 8 9

-9-8-7-6-5-4-3 -2 -1 0 1 2 3 4 5 7 8 g

-9-8-7 -6 -5 -4 -3 -2 -1 0 1

2

3

4

5 6

7

8 9

given that

[tex]|2x+4|>8[/tex]consider the chances,

[tex]2x+4>8[/tex][tex]2x<4[/tex][tex]x<2[/tex][tex]-2x-4<8[/tex][tex]-2x<12[/tex][tex]x>-6[/tex]therefore x lies between -6 and 2

[tex]-6er 10 ft long rests against a vertical wall. if the bottom of the ladder slides away from the wall at a rate of 0.5 ft/s, how fast is the angle between the ladder and the ground changing when the bottom of the ladder is 8 ft from the wall?

The **angle between the ladder** and the ground changes when the bottom of the ladder is 8 ft from the wall is -1/12 **radians** per second.

Denoting the distance in feet between the wall and the base of the ladder by x and the angle in **radians** between the ladder and the ground by y, it is noted;

cos(y) = x/10

which implies;

y = arccos(x/10)

Denoting time in seconds by t, it is further noted that;

[tex]\frac{dx}{dy} = \frac{dy}{dx} \frac{dx}{dt}[/tex] (**chain rule**)

Noting (using a standard table of derivatives for convenience)

[tex]\frac{dy}{dx}= -\frac{1}{\sqrt{1-(0.1x)^2} }(0.1)[/tex] (also by chain rule)

The above equation changes as;

[tex]\frac{dy}{dx}= -\frac{0.1}{\sqrt{1-0.1x^2} }[/tex]

It is noted from the question that in this particular system;

[tex]\frac{dx}{dt} = 0.5[/tex] feet per second

So (denoting the **derivative** as a function of x)

[tex]\frac{dy}{dt}(x)=\frac{dy}{dx} \frac{dx}{dt} = - \frac{0.05}{\sqrt{1-0.01x^2} }[/tex]

At last;

[tex]\frac{dy}{dt}(8)=\frac{dy}{dx} \frac{dx}{dt} = - \frac{0.05}{\sqrt{1-0.01(64)} }[/tex]

= [tex]\frac{0.05}{\sqrt{1-0.64} }[/tex]

= [tex]\frac{-0.05}{\sqrt{0.36} }[/tex]

= -5/60

= -1/12 radians per second

The angle between the ladder and the ground changes when the bottom of the ladder is 8 ft from the wall is -1/12 **radians** per second.

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The formula for the area of the shaded region on the diagram is: Area of the circle - Area of the square The area of the circle is 78.1 cm² rounded to 1 decimal place. The area of the square is 21.4 cm² truncated to 1 decimal place. Write the error interval for the area, a, of the shaded region in the form m < a < n

The **error interval** for the **area** will be expressed as 64.2< a < 63.93

**Error intervals **may be defined as the limits of **accuracy** when a number has been rounded or truncated. They are the range of possible values that a number could have been before it was **rounded** or truncated. According to the question, Area of circle = 78.1 cm² and Area of square = 21.4 cm². If we round the area to one **decimal point**, we get the Area of circle = 78.1 + 0.05 and = 78.1 - 0.05 that is 78.15 and 78.05. Also, the Area of square = 21.4 - 0.05 and = 21.4 + 0.05 we get 21.35 and 21.45. Now, Area of **shaded region** in the form m < a < n. So, n = 78.15 - 21.35

=> n= 56.8 and

m = 78.05 - 21.45

=> m = 56.6

**Area** of shaded region is 56.6< a < 56.8.

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answer choices:

6cm by 1.5cm

10cm by 2cm

13cm by 4cm

18cm by 4.5cm

80cm by 20cm

worth 23 points! and i will give brainly , pls hellpppp

**Answer:**

6cm by 1.5cm

18cm by 4.5cm

80cm by 20cm

**Step-by-step explanation:**

Question

What is the value of m?

0.61m−1.51m=9

0.61m-1.51m=

-0.9m=9

m=-10

-0.9m=9

m=-10

The** value **of m = -10, which we get by solving the given **equation**

The given **equation** is

0.61m - 1.51m = 9

⇒-0.9m = 9 (we get the minus sign because 0.61 is smaller than 1.51)

⇒-0.9m/(-0.9) = 9/(-0.9) (dividing both sides of the equation by -0.9)

⇒m = -90/9

⇒m = -10

Thus on **solving** the given **equation** we get the **value **of m as -10

That is m=-10

Solve another **equation** for x

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(24÷ 3) x 4-(30 ÷ 3)

**Answer:**

22

**Step-by-step explanation:**

Find f (0) please help me. I need this turned in by 11:59 tonight

The value of the **function f(0)** = 1, obtained from the **graph**.

For the given question;

The graph for the function is given.

For finding the value of function f(0), simply see the value of y with respect to x = 0.

f(0) = 1, taken from **graph**.

Thus, the value of** function f(0) **is found as 1.

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write 70 1/3% as a fraction in simplest form.

How to get the answer is the main question for me. I got it wrong on the assignment.

The fraction 70 1/3% in simplest form is **2****4****.****6****7****%****.**

Firstly converting mixed fraction to fraction. For conversion to fraction rewriting the fraction -

Fraction = (3×70 + 1)/3%

Then performing the **multiplication** in numerator of the fraction to find the fraction in simplest form

Fraction = (73 + 1)/3%

Performing **addition** in numerator of the fraction to find the fraction in simplest form

Fraction = 74/3 %

We have got the improper fraction as numerator is greater than denominator. Now performing **division** to find the fraction in simplest form

Fraction = 24.67%

Thus, the fraction in simplest form is **2****4****.****6****7****%**

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Find the value of x.

Round to the nearest tenth.

28 22 11

Please help!!

**Step-by-step explanation:**

your teacher gave you the law of sines already.

this was the only "trick" needed to solve this.

now, we just need to use it.

to be considered : a, b, c are always the sides opposite to the angles A, B, C.

so,

sin(28)/11 = sin(x)/22

sin(x) = 22×sin(28)/11 = 2×sin(28) = 0.938943126...

x = 69.87481894...° ≈ 69.9°

Please Help, Urgent and in detail

**z = **[tex]\frac{13}{20}+\frac{19}{20}i[/tex]** **is in the form **z = a+ ib, **where a = 13/20 and b = 19/20

Exact value of** |z| = 1.151**

**Argument** of z = **55.6197**

Consider the** complex number **z = (2+7i)/(6+2i)

6a. Here z is in a rational form and we need to simplify it to represent it in the form a+ ib.

Multiplying and dividing the conjugate of the denominator to z, we get,

z = [tex]\frac{2+7i}{6+2i} \times \frac{6-2i}{6-2i}[/tex]

⇒ z = [tex]\frac{12 +38i +14}{6^2+2^2}[/tex]

⇒ z = [tex]\frac{26+38i}{40}[/tex]

⇒ z = [tex]\frac{13}{20}+\frac{19}{20}i[/tex]

is in the form **z = a+ ib,** where a = 13/20 and b = 19/20

6b.**modulus of z **= |z| = √(a²+b²)

= [tex]\sqrt{\frac{13^2}{20^2} +\frac{19^2}{20^2} }[/tex]

= [tex]\sqrt{\frac{530}{400}}[/tex]

= √(53/40)

= **1.151**

6c.** Argument **of z = tan⁻¹(b/a)

= tan⁻¹((19/20)/(13/20))

= tan⁻¹(19/13)

= **55.6197**

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10. Find the zero of the function

Hint: put the equation into

standard form and then solve for x.

below(x-intercept).

f(x) = x - 8

A **zero function** is a constant function for which, regardless of the inputs, the output value is always zero.A zero function's input can be any real number, but its output is always zero, hence it can take any value from the **real numbers**

**Solve the problem ?**

The function **f (x) = x - 8** has zeros.

To make f (x) = x - 8 = 0, find x.

Start by factoring f (x),

then f(x) =(x-8)=0

**f (8 ) = 0**

** x = 8**

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Solve the question on the image attached.

Possible answers:

A) 1

B) 3

C) 5

Should be **B.**

There is a nested function structure. Let's first look at the limit of the interior (f(0)). The point we need to pay attention here is to look at the limits from the right and left. If both values are equal, we can say that it has a limit at that point.

If we express it algebraically;

[tex]lim_{x\to{0^-}}f(x)=lim_{x\to{0^+}}f(x)[/tex] then,[tex]lim_{x\to{0}}f(x)=exist[/tex]The left limit and the right limit of [tex]f(0)[/tex] are equal and equal to [tex]2.[/tex]

[tex]lim_{x\to{0^-}}f(x)=2[/tex][tex]lim_{x\to{0^+}}f(x)=2[/tex]The left limit and the right limit of f(2) are equal and equal to 3.

[tex]lim_{x\to{2^-}}f(x)=3[/tex][tex]lim_{x\to{2^+}}f(x)=3[/tex]As I have drawn with colored arrows in the graph below, we approach from the left and from the right, and if they both point to the same point, we can talk about the existence of the limit at that point. Otherwise, this function does not have a limit at that point.

Georgina has a total of $5000 invested in a savings account that receives 0.6% APY and a CD that receives 0.9% APY. How much does she have invested in each account if her total annual interest earned is $37.50?

The **amount **that Georgina has invested in savings account and CD are $ 2500 each.

Given that:-

Total amount invested in savings account and CD = $ 5000.

APY in **savings account** = 0.6 %

APY in CD = 0.9 %

Total interest earned = $ 37.5

Let the amount invested in savings account be x.

Hence, according to the data given in the **question**, we can write,

**Amount invested** in CD = 5000 - x

**Interest** in savings account in a year = x*(0.6)*1/100 = 0.006x

Interest in CD in a year = (5000-x)*(0.9)*1/100 = (0.009)(5000-x) = 45 - 0.009x

Hence,

0.006x + 45 - 0.009x = 37.5

45 - 37.5 = 0.009x-0.006x

7.5 = 0.003x

x = 7.5/(0.003)

x = 7500/3 = 2500

Hence, Georgina has **invested** $2500 in each savings account and CD.

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i have no clue how to do this someone pls help me

Using **proportions**, it is found that:

**a) **The **graph **for the distance-time journey is given at the end of the answer.

**b) **The **average **speed for the whole journey was of 25 miles per hour.

A proportion is a **fraction **of a total amount, and equations can be built to find the desired measures in the problem using basic arithmetic operations such as multiplication or division from the rates of the variables.

Proportions are applied to find the **relation **between velocity, distance and time, as velocity is distance divided by time, that is:

v = d/t.

Then, applying cross multiplication, the **distance **is given by:

d = vt.

On the** first interval** of his trip, for the first 15 minutes = 1/4 of an hour, he traveled at a velocity of 40 mph, hence the **distance **is:

d = 40 x 1/4 = 10 miles.

During the **second **interval, of 25 minutes, from 15 minutes to 40 minutes, he stopped, hence his distance remained **constant **at 10 miles.

During the **third **interval, of 20 minutes = 1/3 of an hour, Tim completed the journey at a velocity of 45 mph, hence the** complete distance** is given by:

d = 10 + 45 x 1/3 = 10 + 15 = 25 miles.

The **graph **with these three intervals is given at the end of the answer.

He drove a distance of 25 miles in one hour, hence his **average speed** is given as follows:

v = d/t = 25/1 = 25 miles per hour.

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many subjects don’t give honest answers to questions about activities that are illegal or sensitive in some other way. one study divided a large group of white adults into thirds at random. all were asked if they had ever used cocaine. the first group was interviewed by telephone: 21% said "yes." in the group visited at home by an interviewer, 25% said "yes." the final group was interviewed at home but answered the question on an anonymous form that they sealed in an envelope. of this group, 28% said they had used cocaine.

**28% is the correct answer because it is the closest to true value sine people are sensitive about information like this.**

2/3 + 1/4 + 1/2 = x/12 , so what is x?

**Answer:**

Solve for x by simplifying both sides of the equation, then isolating the variable.

x=17

**Step-by-step explanation:**

What is the slope of the line that passes through the points (-8, -6)(−8,−6) and (-8, 4)(−8,4)? Write your answer in simplest form.

Use the slope line formula to help you find the slope between the two points.

In this case, the x-values on both points are on the same line, so the slope is UNDEFINED.

In this case, the x-values on both points are on the same line, so the slope is UNDEFINED.

A) The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over times, x measured in seconds. During what interval(s) of the domain is the water balloon's height staying the same?

A.0 ≤ x ≤ 2

B.2 ≤ x ≤ 5

C.5 ≤ x ≤ 6

D.6 ≤ x ≤ 8

B) The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds. During what interval(s) of the domain is the water balloon's height increasing?

A.0 ≤ x ≤ 2

B.40 ≤ y ≤ 70

C.5 ≤ x ≤ 8

D.40 ≤ y ≤ 10

C) The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds. During what interval(s) of the domain is the water balloon's height decreasing the fastest?

A.5 ≤ x ≤ 9.5

B.8 ≤ x ≤ 9.5

C.6 ≤ x ≤ 8

D.5 ≤ x ≤ 6

D) The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds. Justify your answer from Part C.

A.5 ≤ x ≤ 9.5 is the interval where the balloon's height is decreasing.

B.8 ≤ x ≤ 9.5 is the interval where the slope is the steepest.

C.6 ≤ x ≤ 8 is the interval where the balloon's height decreases the most.

D.5 ≤ x ≤ 6 is the interval where the slope is the steepest.

Please help as fast as possible <3

As shown in the reference **graph **attached hereby with the question statement, if the linear model represents the height, f(x), of a water balloon thrown off the roof of a building over **time** "x" measured in seconds, then,

(A) During (2 ≤ x ≤ 5) seconds in the **time domain**, the water balloon's height remains the same.

(B) During (0 ≤ x ≤ 2) seconds, the **height **of the water balloon is increasing.

(C) During (5 ≤ x ≤ 6) seconds, the **height** of the water balloon decreases the fastest.

(D) From Part (C), it can be justified that 5 ≤ x ≤ 9.5 is the interval where the balloon's height is decreasing, and, (5 ≤ x ≤ 6) is the interval where the **slope** is the steepest.

As per the question statement and the reference **graph** attached alongside, the linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time "x" measured in seconds.

We are required to determine the correct **time domains** for four different situations, by observing the plotted graph.

Part (A) is to determine the correct **time domain** where the water balloon's height remains the same.

From the graph, it is clear that, the height remains constant at (y = 70), parallel to the x-axis from the 2nd second to the 5th second. Hence, During (2 ≤ x ≤ 5) seconds in the **time domain**, the water balloon's height remains the same.

Part (B) is to determine the correct **time domain** where the height of the water balloon is increasing.

From the graph, it is clear that, the slope of the concerned graph rises only from [(y = 40) to (y = 70)], starring from the 0th second until the 2nd second. Hence, During (0 ≤ x ≤ 2) seconds in the **time domain**, , the height of the water balloon is increasing.

Part (C) is to determine the correct **time domain** where the height of the water balloon decreases the fastest.

From the graph, it is clear that, the graph decreases thrice, first from [(y = 70) to (y = 40)], starting at the 5th second uptil the 6th second, then from [(y = 40) to (y = 10)], starting at the 6th second uptil the 9th second and lastly, from [(y = 10) to (y = 0)], starting at the 9th second till the 9.5th second. Here, we can easily calculate that, the balloon dropped 30ft in 1 sec at the first instance, 30ft in 3 seconds at the second instance and, 10ft in 0.5 seconds.

Since, [(30/1) > (10/0.5) > (30/3)],

Or, [30 > 20 > 10],

Thus, During (5 ≤ x ≤ 6) seconds, the height of the water balloon decreases the fastest.

Part (D) is to determine the correct statement mentioned under it's options, with judgement based on Part (C).

Option (i) states that [(5 ≤ x ≤ 9.5) is the interval where the balloon's height is decreasing] which is true, as we can observe from the graph that the slope is decreasing during the time interval of 5 to 9.5th seconds, although at different rates at different intervals.

Option (ii) states that [(8 ≤ x ≤ 9.5) is the interval where the slope is the steepest] which means that, during this above said interval, the height of the balloon drops the fastest which is false, as we have already proved in part (C) that during (5 ≤ x ≤ 6) seconds, the height of the water balloon decreases the fastest.

Option (iii) states that, [(6 ≤ x ≤ 8) is the interval where the balloon's height decreases the most] which is false, as balloons height falls the farthest by 30fts in two separate intervals, between (5 ≤ x ≤ 6) seconds and (6 ≤ x ≤ 9) seconds.

Finally, Option (iv) states that [(5 ≤ x ≤ 6) is the interval where the slope is the steepest] which means that, during this above said interval, the height of the balloon drops the fastest which is true, as we have already proved in part (C) that during (5 ≤ x ≤ 6) seconds, the height of the water balloon decreases the maximum in the shortest time period.

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A person randomly selects one of six envelopes Each envelope contains a check that the person gets to keep. Determine the person's expectation if three envelopes contain a 491 check and three envelopes contain a 51003 checkThe expected value is $(Simplify your anwwer Type an integer or a decimal)

The probability formula is given by:

[tex]\text{ P(E) =}\frac{\text{ N(Required outcome)}}{\text{ N(Total outcome)}}[/tex]The person selects one of six envelopes.

There is a probability that the person selects an envelope that contains a $491 of 3 envelopes OR an envelope that contains a $1003 check of 3 envelopes

[tex]\begin{gathered} \text{ P(select one containing \$491 check) =}\frac{3}{6}=\frac{1}{2} \\ \text{ P(select one containing \$1003 check) =}\frac{3}{6}=\frac{1}{2} \end{gathered}[/tex]Then, the expected value is given by

[tex]\begin{gathered} \text{ P(Expected Value) =(}\frac{1}{2}\times491)\text{ +(}\frac{1}{2}\times1003) \\ =245.5+501.5 \\ =747.0 \end{gathered}[/tex]

Apple Picking

Name

josiph

Linda and Robin went apple picking. After picking all day, Linda had 15 more

apples than Robin. Together, they gathered 105 apples. Figure out how many

apples Linda got and how many Robin got. Linda got 1/3 of all her apples from

the first tree and % of all her apples from the second tree. She got the rest of her

apples from the third tree. Robin got 1/3 of all her apples from the first tree and

5/9 of all her apples from the second tree. She got the rest of her apples from

the third tree. Who got more apples from the third tree? How many more?

We can write the **system of equations:**

x = y + 15

x + y = 105

Solving the **system**, we will see that Robin has 45 apples and Linda 60 apples.

Here we can only solve the first part, as the second is incomplete.

Let's define the **variables**:

x = apples that Linda has.

y = apples that Robin has.

We know that Linda has 15 more apples than Robin, and that between the two there are 105 apples, so we can write the** system of equations:**

x = y + 15

x + y = 105

To solve this, we can replace the first equation into the second one, so we get:

(y + 15) + y = 105

2y + 15 = 105

2y = 105 - 15 = 90

y = 90/2 = 45

So Robin has 45 apples, and Linda has 15 more, so she has:

x = 45 + 15 = 60

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100x20x10+2=

pls iam doing a test and the calculator is blocked

**Answer:**

20002

**Step-by-step explanation:**

100*20=2000

2000*10=20000

20000+2=20002

On a coordinate plane, a graph decreases between (2.5, 2) and (4.5, 0.25).

How does this graph change between (2.5, 2) and (4.5, 0.25)?

The graph of the **coordinate **plane is attached below.

Any point on a plane can be uniquely identified by a pair of numerical **coordinates **using a cartesian **coordinate **system, which employs signed distances between two fixed **perpendicular** oriented lines and the point measured in the same unit of length.

The graph of the line **decreases **between (2.5, 2) and (4.5, 0.25) and the graph **increases **between (2.5, 2) and (4.5, 0.25)

To learn more about **coordinates **visit:

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